Find the 10th term in the expansion of `(2x^(2)+1/x)^(12)`.

Explanation

To find the 10th term in the expansion of \((2x^2 + \frac{1}{x})^{12}\), we will use the Binomial Theorem. The Binomial Theorem states that:

\[ (a + b)^n = \sum_{r=0}^{n} \binom{n}{r} a^{n-r} b^r \]

In our case, \(a = 2x^2\), \(b = \frac{1}{x}\), and \(n = 12\).

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