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Evaluate: inte^x(x^2+1)/((x+1)^2)\ dx...

Evaluate: `inte^x(x^2+1)/((x+1)^2)\ dx`

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We have `I=inte^(x)*((x^(2)+1))/((x+1)^(2))dx=inte^(x)*{((x+1)^(2)-2x)/((x+1)^(2))}dx`
`=inte^(x)*{1-(2x)/((x+1)^(2))}dx=inte^(x)dx-2int*(x)/((x+1)^(2))dx`
`=e^(x)-2*inte^(x)*({(x+1)-1})/((x+1)^(2))dx=e^(x)*{(1)/((x+1))-(1)/((x+1)^(2))}dx`
`=e^(x)-2*inte^(x){f(x)+f'(x)}dx,"where"f(x)=(1)/((x+1))andf'(x)=(-1)/((x+1)^(2))`
`=e^(x)-2e*f(x)+C=e^(x)-2e^(x).(1)/((x+1))+C`
`=e^(x)*{1-(2)/((x+1))}+C=e^(x)((x-1)/(x+1))+C`.
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