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intsec^(2)(7-4x)dx=?...

`intsec^(2)(7-4x)dx=?`

A

`(1)/(4)tan(7-4x)+C`

B

`(-1)/(4)tan(7-4x)+C`

C

`4tan(7-4x)+C`

D

`-4tan(7-4x)+C`

Text Solution

Verified by Experts

The correct Answer is:
B
Put (7-4x)=t and -4dx = dt.
`:." "I=-(1)/(4)sec^(2)tdt=-(1)/(4)tan t+C`.
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