intcos3xdx=?...

`intcos3xdx=?`

A

`-(1)/(3)sin3x+C`

B

`(1)/(3)sin3x+C`

C

`3sin3x+C`

D

`-3sin3x+C`

Text Solution

Verified by Experts

The correct Answer is:

B

Put 3x=t and 3dx=dt.

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RS AGGARWAL-METHODS OF INTEGRATION -Objective Questions I

intsqrt(ax+b)dx=?
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intsec^(2)(7-4x)dx=?
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intcos3xdx=?
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inte^((5-3x))dx=?
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intsqrt(1+sinx)dx
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intsin^(3)xdx=?
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int(logx)/(x)dx=?
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int (sec^(2)(logx ))/(x)dx
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int(1)/(x(logx))dx=?
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inte^(x^(3))x^(2)dx=?
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int \ (e^(sqrt(x)))/(sqrt(x))dx
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Evaluate: int(e^tan^((-1)x))/(1+x^2)\ dx
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int(sinsqrt(x))/(sqrt(x))dx=?
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int(sqrt(sinx))cosxdx=?
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Evaluate: int1/(sqrt(t a n^(-1)x)(1+x^2))dx
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int(cotx)/(log(sinx))dx
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int(1)/(xcos^(2)(1+logx))dx=?
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