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intsecxdx=?...

`intsecxdx=?`

A

`log|secx-tanx|+C`

B

`-log|secx+tanx|+C`

C

`log|secx+tanx|+C`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
C
`I=int(secx(secx+tanx))/((secx+tanx))dx=int(1)/(t)`dt, where (secx+tanx)=t.
`=log|t|+C=log|secx+tanx|+C`.
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