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inttanx/(secx+cosx)dx...

`inttanx/(secx+cosx)dx`

A

`tan^(-1)(cosx)+C`

B

`-tan^(-1)(cosx)+C`

C

`cot^(-1)(cosx)+C`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
B
`I=int(sinx)/(1+cos^(2)x)dx=-int(1)/((1+t^(2)))` dt, where cos x=t.
`=-tan^(-1)t+C=-tan^(-1)(cosx)+C`.
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