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int3^((5-3x))dx=?...

`int3^((5-3x))dx=?`

A

`(-3^((5-3x)))/(3(log3))+C`

B

`(3^((4-3x)))/((log3))+C`

C

`-3^((5-3x))log3+C`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
A
Put 5-3x=t and-3x dx=dt.
`:." "I=-(1)/(3)int3^(t)dt=-(1)/(3)dt=-(1)/(3)xx(3^(t))/(log3)+C=-(1)/(3)xx(3^((5-3x)))/(log3)+C`.
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