intsinxlog(cosx)dx=?...

`intsinxlog(cosx)dx=?`

Text Solution

Verified by Experts

The correct Answer is:

`cosx(1-logcosx)+C`

Put cos x=t.

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RS AGGARWAL-METHODS OF INTEGRATION -Exercise 13C

Evaluate the following integrals: int"cosec"^(3)xdx
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Evaluate the following integrals: intxsin^(3)xcosxdx
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intsinxlog(cosx)dx=?
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Evaluate the following integrals: int(log(logx))/(x)dx
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Evaluate the following integrals: intlog(2+x^(2))dx
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Evaluate the following integrals: int(x)/((1+sinx))dx
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Evaluate the following integrals: int{(1)/(logx)-(1)/((log)^(2))}dx
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Evaluate the following integrals: inte^(x)cos2xcos4xdx
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Evaluate the following integrals: inte^(sqrt(x))dx
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Evaluate the following integrals: inte^(sinx)sin2xdx
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Evaluate the following integrals: int(xsin^(-1)x)/(sqrt(1-x^(2)))dx
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Evaluate the following integrals: int(x^(2)tan^(-1)x)/((1+x^(2)))dx
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Evaluate the following integrals: int(log(x+2))/((x+2)^(2))dx
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Evaluate the following integrals: intxsin^(-1)xdx
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Evaluate the following integrals: intxcos^(-1)xdx
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Evaluate the following integrals: intcot^(-1)xdx
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Evaluate the following integrals: intxcot^(-1)xdx
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Evaluate the following integrals: intx^(2)cot^(-1)xdx
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Evaluate the following integrals: intsin^(-1)sqrt(x)dx
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Evaluate the following integrals: intcos^(-1)sqrt(x)dx
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