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Let A and B be two events such that P(A|...

Let A and B be two events such that P(A|B) = P(A'|B') = p and P(B) = 0.05. The value of p so that P(B|A) =0.9 is

A

`21//430`

B

`173//430`

C

`171//430`

D

`95//430`

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The correct Answer is:
To solve the problem step by step, we will use the given information about the probabilities of events A and B. ### Step 1: Understand the Given Information We know: - \( P(A|B) = p \) - \( P(A'|B') = p \) - \( P(B) = 0.05 \) - We want to find \( p \) such that \( P(B|A) = 0.9 \). ### Step 2: Use the Definition of Conditional Probability From the definition of conditional probability, we can express \( P(A|B) \) and \( P(B|A) \) as follows: \[ P(A|B) = \frac{P(A \cap B)}{P(B)} \] \[ P(B|A) = \frac{P(B \cap A)}{P(A)} \] Since \( P(A \cap B) = P(B \cap A) \), we can denote \( P(A \cap B) = X \). ### Step 3: Express \( P(A|B) \) in Terms of \( X \) Substituting the known values into the equation for \( P(A|B) \): \[ p = \frac{X}{0.05} \quad \text{(1)} \] ### Step 4: Express \( P(B|A) \) in Terms of \( P(A) \) Let \( P(A) = Y \). Then, we can express \( P(B|A) \): \[ 0.9 = \frac{X}{Y} \quad \text{(2)} \] ### Step 5: Use the Complementary Probability Using the information about \( P(A'|B') \): \[ P(A'|B') = \frac{P(A' \cap B')}{P(B')} \] Using De Morgan's theorem, we can express \( P(A' \cap B') \): \[ P(A' \cap B') = P((A \cup B)') = 1 - P(A \cup B) \] Using the formula for the union of two events: \[ P(A \cup B) = P(A) + P(B) - P(A \cap B) = Y + 0.05 - X \] Thus, \[ P(A' \cap B') = 1 - (Y + 0.05 - X) = 0.95 - Y + X \] Now substituting into the equation for \( P(A'|B') \): \[ p = \frac{0.95 - Y + X}{0.95} \quad \text{(3)} \] ### Step 6: Substitute \( X \) and \( Y \) in Terms of \( p \) From equation (1), we have: \[ X = 0.05p \] From equation (2): \[ Y = \frac{X}{0.9} = \frac{0.05p}{0.9} = \frac{p}{18} \] ### Step 7: Substitute \( X \) and \( Y \) into Equation (3) Substituting \( X \) and \( Y \) into equation (3): \[ p = \frac{0.95 - \frac{p}{18} + 0.05p}{0.95} \] ### Step 8: Solve for \( p \) Multiplying both sides by \( 0.95 \): \[ 0.95p = 0.95 - \frac{p}{18} + 0.05p \] Combining like terms: \[ 0.95p + \frac{p}{18} - 0.05p = 0.95 \] This simplifies to: \[ 0.9p + \frac{p}{18} = 0.95 \] Finding a common denominator (which is 18): \[ \frac{16.2p + p}{18} = 0.95 \] \[ \frac{17.2p}{18} = 0.95 \] Now, multiply both sides by 18: \[ 17.2p = 17.1 \] Finally, solving for \( p \): \[ p = \frac{17.1}{17.2} = \frac{171}{172} \] ### Final Answer Thus, the value of \( p \) is \( \frac{171}{172} \). ---
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