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Let A = [{:("cos"alpha, -"sin"alpha), ("...

Let `A = [{:("cos"alpha, -"sin"alpha), ("sin"alpha, "cos"alpha"):}], (alpha in R)` such that `A^(32) = [{:(0, -1), (1, 0):}]`. Then, a value of `alpha` is

A

`(pi)/(32)`

B

0

C

`(pi)/(64)`

D

`(pi)/(16)`

Text Solution

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The correct Answer is:
C
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