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If `[{:(1, 1), (0,1):}]*[{:(1, 2), (0,1):}]*[{:(1, 3), (0,1):}]cdotcdotcdot[{:(1, n-1), (0,1):}] = [{:(1, 78), (0,1):}]`, then the inverse of `[{:(1, n), (0,1):}]` is

A

`[(1,0),(12,1)]`

B

`[(1,-13),(0,1)]`

C

`[(1,-12),(0,1)]`

D

`[(1,0),(13,1)]`

Text Solution

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The correct Answer is:
C
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