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The equation of tangent to the curve y=i...

The equation of tangent to the curve `y=int_(x^2)^(x^3)(dt)/(1+t^2)` at `x=1` is `sqrt(3)x+1=y` (b) `sqrt(2)y+1=x` `sqrt(3)x+y=1` (d) `sqrt(2)y=x`

A

`sqrt2 y-1 =x`

B

`sqrt3 x-1 =y`

C

`sqrt3 x+ 1=y`

D

`sqrt2 y+1 =x`

Text Solution

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The correct Answer is:
D
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