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If PQ is a focal chord of the parabola y...

If PQ is a focal chord of the parabola `y^(2)=4ax` with focus at s, then `(2SP.SQ)/(SP+SQ)=`

A

a

B

2a

C

4a

D

`a^(2)`

Text Solution

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The correct Answer is:
To solve the problem, we need to find the value of \(\frac{2SP \cdot SQ}{SP + SQ}\) for the focal chord \(PQ\) of the parabola \(y^2 = 4ax\) with focus at \(S\). ### Step-by-step Solution: 1. **Identify the Focus of the Parabola**: The given parabola is \(y^2 = 4ax\). The focus of this parabola is at the point \(S(a, 0)\). **Hint**: Recall that for a parabola in the form \(y^2 = 4ax\), the focus is located at \((a, 0)\). 2. **Understanding Focal Chords**: A focal chord is a line segment that passes through the focus of the parabola. Let \(P\) and \(Q\) be the endpoints of the focal chord. 3. **Using the Property of Focal Chords**: For any focal chord \(PQ\) of the parabola \(y^2 = 4ax\), the following property holds: \[ \frac{1}{SP} + \frac{1}{SQ} = \frac{2}{l} \] where \(l\) is the length of the semi-latus rectum. The length of the semi-latus rectum for the parabola \(y^2 = 4ax\) is \(2a\). **Hint**: Remember that the semi-latus rectum is a fixed distance related to the parabola's focus. 4. **Substituting the Length of the Semi-latus Rectum**: Since the semi-latus rectum \(l = 2a\), we can substitute this into the equation: \[ \frac{1}{SP} + \frac{1}{SQ} = \frac{2}{2a} = \frac{1}{a} \] 5. **Finding the Values of \(SP\) and \(SQ\)**: Let \(SP = p\) and \(SQ = q\). Then we have: \[ \frac{1}{p} + \frac{1}{q} = \frac{1}{a} \] This can be rewritten as: \[ \frac{p + q}{pq} = \frac{1}{a} \] Cross-multiplying gives: \[ a(p + q) = pq \] 6. **Rearranging the Equation**: Rearranging the equation gives: \[ pq = ap + aq \] 7. **Finding the Value of \(\frac{2pq}{p + q}\)**: Now, we need to find: \[ \frac{2pq}{p + q} \] From our previous step, we know \(pq = a(p + q)\). Substituting this into our expression gives: \[ \frac{2pq}{p + q} = \frac{2a(p + q)}{p + q} = 2a \] ### Final Answer: Thus, the value of \(\frac{2SP \cdot SQ}{SP + SQ}\) is \(2a\).
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