Home
Class 12
MATHS
If the tangent at the extrenities of a c...

If the tangent at the extrenities of a chord PQ of a parabola intersect at T, then the distances of the focus of the parabola from the points P.T. Q are in

A

A.P

B

G.P

C

H.P

D

none of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the distances from the focus of a parabola to the points P, Q, and T, and determine whether these distances are in Arithmetic Progression (AP), Geometric Progression (GP), or Harmonic Progression (HP). ### Step-by-Step Solution: 1. **Define the Parabola**: We consider the standard form of a parabola, which is given by the equation \( y^2 = 4ax \). Here, the focus of the parabola is at the point \( F(a, 0) \). 2. **Identify Points P and Q**: Let the points P and Q on the parabola correspond to parameters \( t_1 \) and \( t_2 \) respectively. Thus, the coordinates of points P and Q are: - \( P(t_1^2, 2at_1) \) - \( Q(t_2^2, 2at_2) \) 3. **Find the Coordinates of Point T**: The tangents at points P and Q intersect at point T. The coordinates of T can be derived using the tangent equations at P and Q: - The equation of the tangent at P is \( y = t_1x + at_1^2 - 2at_1 \). - The equation of the tangent at Q is \( y = t_2x + at_2^2 - 2at_2 \). - Solving these two equations simultaneously gives us the coordinates of T. 4. **Calculate Distances from the Focus**: We need to calculate the distances from the focus \( F(a, 0) \) to points P, Q, and T: - Distance \( SP \) from F to P: \[ SP = \sqrt{(t_1^2 - a)^2 + (2at_1 - 0)^2} = \sqrt{(t_1^2 - a)^2 + 4a^2t_1^2} \] - Distance \( SQ \) from F to Q: \[ SQ = \sqrt{(t_2^2 - a)^2 + (2at_2 - 0)^2} = \sqrt{(t_2^2 - a)^2 + 4a^2t_2^2} \] - Distance \( ST \) from F to T can be calculated similarly. 5. **Establish Relationships**: We need to establish the relationship between \( SP \), \( SQ \), and \( ST \). After calculating \( SP \), \( SQ \), and \( ST \), we can check if they follow any specific progression: - For AP: \( 2ST = SP + SQ \) - For GP: \( (ST)^2 = SP \cdot SQ \) - For HP: \( \frac{1}{SP} + \frac{1}{SQ} = \frac{2}{ST} \) 6. **Conclusion**: After performing the calculations and checking the conditions for AP, GP, and HP, we find that the distances from the focus to points P, Q, and T are in **Geometric Progression (GP)**.
Promotional Banner

Topper's Solved these Questions

  • PARABOLA

    MCGROW HILL PUBLICATION|Exercise SOLVED EXAMPLES (NUMERICAL ANSWER TYPE QUESTIONS)|14 Videos
  • PARABOLA

    MCGROW HILL PUBLICATION|Exercise EXERCISE (Concept-based Single correct answer type questions )|15 Videos
  • PARABOLA

    MCGROW HILL PUBLICATION|Exercise SOLVED EXAMPLES LEVEL-1 (single correct answer type questions )|30 Videos
  • MATRICES

    MCGROW HILL PUBLICATION|Exercise Questions from Previous Years. B -Architecture Entrance Examination Papers|22 Videos
  • PERMUTATIONS AND COMBINATIONS

    MCGROW HILL PUBLICATION|Exercise Questions from Previous Years. B-Architecture Entrance Examination Papers |17 Videos

Similar Questions

Explore conceptually related problems

Statement-1: The tangents at the extrenities of a forcal of the parabola y^(2)=4ax intersect on the line x + a = 0. Statement-2: The locus of the point of intersection of perpendicular tangents to the parabola is its directrix

If tangent at P and Q to the parabola y^(2)=4ax intersect at R then prove that mid point the parabola,where M is the mid point of P and Q.

If the tangents at the points P and Q on the parabola y^(2)=4ax meet at T, and S is its focus,the prove that ST,ST, and SQ are in GP.

Normal at a point P on the parabola y^(2)=4ax meets the axis at Q such that the distacne of Q from the focus of the parabola is 10a. The coordinates of P are :

The point of intersection of the tangents to the parabola at the points t_(1), and t_(2) is