Let l be the length of the latus rectum of the parabola whose focus is (1,2) and two tangents are `x-y=0 and x+y=0`, then l is equal to `(sqrt5=2.24)`

Answer

To solve the problem, we need to find the length of the latus rectum of the parabola given its focus and two tangents. Here’s a step-by-step solution:

### Step 1: Identify the Focus and Tangents
The focus of the parabola is given as \( S(1, 2) \). The tangents are given by the equations \( x - y = 0 \) (which simplifies to \( y = x \)) and \( x + y = 0 \) (which simplifies to \( y = -x \)).