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The points of intersection of the circle...

The points of intersection of the circle `x^2 + y^2= a^2` with the parabolas `y^2= 4ax and y^2=-4ax` form a rectangle whose area is

A

`8(sqrt5-2)a^(2)`

B

`8(sqrt5-2)^(3//2)a^(2)`

C

`8(sqrt5+2)^(3//2)a^(2)`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
B
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