Home
Class 12
MATHS
The number of common chords of the parab...

The number of common chords of the parabola `y=x^(2)-x and x=y^(2)-y` is

Text Solution

AI Generated Solution

The correct Answer is:
To find the number of common chords of the parabolas \( y = x^2 - x \) and \( x = y^2 - y \), we will follow these steps: ### Step 1: Set the equations equal to each other We have two parabolas: 1. \( y = x^2 - x \) 2. \( x = y^2 - y \) To find the points of intersection, we can substitute \( y \) from the first equation into the second equation. ### Step 2: Substitute \( y \) into the second equation Substituting \( y = x^2 - x \) into \( x = y^2 - y \): \[ x = (x^2 - x)^2 - (x^2 - x) \] ### Step 3: Simplify the equation Now, let's simplify the equation: \[ x = (x^2 - x)^2 - (x^2 - x) \] Expanding \( (x^2 - x)^2 \): \[ = x^4 - 2x^3 + x^2 \] So, we rewrite the equation: \[ x = x^4 - 2x^3 + x^2 - x^2 + x \] This simplifies to: \[ x = x^4 - 2x^3 \] Rearranging gives: \[ x^4 - 2x^3 - x = 0 \] ### Step 4: Factor the equation Factoring out \( x \): \[ x(x^3 - 2x^2 - 1) = 0 \] Thus, we have: 1. \( x = 0 \) 2. \( x^3 - 2x^2 - 1 = 0 \) ### Step 5: Solve the cubic equation Now we need to solve the cubic equation \( x^3 - 2x^2 - 1 = 0 \). We can use numerical methods or graphing to find the roots of this cubic polynomial. ### Step 6: Find the number of real roots Using the Rational Root Theorem or numerical methods, we find that this cubic equation has one real root (approximately \( x \approx 2.879 \)) and two complex roots. ### Step 7: Find corresponding \( y \) values For each \( x \) value we found, we can find the corresponding \( y \) values using the equation \( y = x^2 - x \): 1. For \( x = 0 \): \( y = 0^2 - 0 = 0 \) (Point: (0, 0)) 2. For \( x \approx 2.879 \): Calculate \( y \) using \( y = (2.879)^2 - 2.879 \). ### Step 8: Determine the number of common chords The points of intersection are \( (0, 0) \) and the point corresponding to \( x \approx 2.879 \). Since there are two distinct intersection points, we can draw one common chord between these two points. ### Conclusion Thus, the number of common chords of the given parabolas is **1**. ---
Promotional Banner

Topper's Solved these Questions

  • PARABOLA

    MCGROW HILL PUBLICATION|Exercise QUESTIONS FROM PREVIOUS YEARS. AIEEE/JEE MAIN PAPERS|36 Videos
  • PARABOLA

    MCGROW HILL PUBLICATION|Exercise QUESTIONS FROM PREVIOUS YEARS. B-ARCHITECTRE ENTRANCE EXAMINATION PAPERS|9 Videos
  • PARABOLA

    MCGROW HILL PUBLICATION|Exercise EXERCISE LEVEL-2 (single correct answer type questions )|10 Videos
  • MATRICES

    MCGROW HILL PUBLICATION|Exercise Questions from Previous Years. B -Architecture Entrance Examination Papers|22 Videos
  • PERMUTATIONS AND COMBINATIONS

    MCGROW HILL PUBLICATION|Exercise Questions from Previous Years. B-Architecture Entrance Examination Papers |17 Videos

Similar Questions

Explore conceptually related problems

The number of common chords of the parabolas x=y^(2)-6y+11 and y=x^(2)-6x+11 is 1 (b) 2 (c) 4 (d) 6

The length of the common chord of the parabolas y^(2)=x and x^(2)=y is

The number of common chords of parabola x=y^(2)-6y+1 and y=x^(2)-6x+1 are

Number of common chords of the parabolas x=y^(2)-6y+9 and y=x^(2)-6x+9 are

The number of common tangents to the parabola y^(2)=8x and x^(2)+y^(2)+6x=0 is

The common tangent to the parabolas y^(2)=8x and x^(2)=-4y is

The common tangent of the parabolas y^(2)=4x" and "x^(2)=-8y, is

Length of the common chord of the parabola y^(2)=8x and the circle x^(2)+y^(2)-2x-4y=0 is :