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During the reaction between formic acid ...

During the reaction between formic acid & `KMnO_4`. The equivalent weight of `KMnO_4` obtained by dividing it's molecular weight by a _______ factor

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The correct Answer is:
5
`2KMnO_4 + 3H_2 SO_4 + 5HCOOH to K_2 SO_4 + 5 CO_2 + 8H_2 O`
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