`1/(a^(x))+log_(a)x`का x के सापेक्ष अवलन गुणांक ज्ञात कीजिये ।

Explanation

`(d)/(dx)[(1)/(a^(x))log_(a)x ] = (d)/(dx)(a^(-x)+log_(a)x log_(a) e )`
`=a^(-x)log _(e)a(d)/(dx)(-x)+(1)/(x)log_(a)e`
`=-log_(e)a a^(-x)+(1)/(x)log_(a)e`