`ax^(n)log_(e)x` का x के सापेक्ष अवलन गुणांक ज्ञात कीजिये ।

Explanation

`y=ax^(n)log_(e)x`
`:. (dy)/(dx)=a(d)/(dx)(underset(I)x^(n)underset(II)(log_(e))x)`
`=a{x^(n).(1)/(x)+nx^(n-1)log_(e)x}`
`=a(x^(n-1)+nx^(n-1)log_(e)x)`
`=ax^(n-1)(1+nlog_(e)x)`