Two simple harmonic motion of angular frequency `100and 1000 rads^(-1)` have the same displacement amplitude The ratio of their maximum acceleration is

Options

A. `1:10^(3)`
B. `1:10^(4)`
C. `1:10`
D. `1:10^(2)`

Answer

D

Explanation

Here, `omega_(1)=100" rad s"^(-1),omega_(2)=1000" rad s"^(-1)`
`a_("max"_(1))=omega_(1)^(2)A`
`a_("max"_(2))=omega_(2)^(2)A therefore (a_("max"_(1)))/(a_("max"_(2)))=(omega_(1)^(2))/(omega_(2)^(2))=((100)^(2))/((1000)^(2))=(1)/(100)`