An open pipe is suddenly closed at one end with the result that the frequency of third harmonic of the closed pipe is found to be higher by `100 Hz` then the fundamental frequency of the open pipe. The fundamental frequency of the open pipe is

Explanation

Let the length of the organ pipe = l
When open, fundamental frequency `(upsilon_(1))=v//2l`
When closed, frequency of third harmonic, `upsilon_(2)=3((v)/(4l))`
Given that, `upsilon_(2)=upsilon_(1)+100`
`therefore (3v)/(4l)=(v)/(2l)+100 or v=4lxx100`
`therefore upsilon_(1)=(v)/(2l)=(4lxx100)/(2l)=200Hz`
`therefore` Fundamental frequency of open pipe = 200 Hz.