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A particle executing of a simple harmoni...

A particle executing of a simple harmonic motion covers a distance equal to half its amplitude in on e second . Then the time period of the simple harmonic motion is

A

4 s

B

6 s

C

8 s

D

12 s

Text Solution

Verified by Experts

The correct Answer is:
C
In SHM, `x=Asinomegat=Asin.(2pi)/(T)t`
At `t=1s,x=(A)/(2)therefore (A)/(2)=Asin.(2pi)/(T)or(1)/(2)=sin.(2pi)/(T)`
or `sin.(pi)/(6)=sin.(2pi)/(T)orT=12s`
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