The maximum velocity a particle, executi...

The maximum velocity a particle, executing simple harmonic motion with an amplitude 7 mm, 4.4 m//s. The period of oscillation is.

100 s

0.01 s

10 s

0.1 s

Text Solution

Verified by Experts

The correct Answer is:

Maximum velocity, `v_(m)=Aomega=A((2pi)/(T))`
`therefore T=(2piA)/(v_(m))=2xx(22)/(7)xx(7xx10^(-3))/(4.4)10^(-2)s=0.01s`

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