The angular velocities of three bodies in `SHM` are `omega_(1), omega_(2), omega_(3)` with their respective amplitudes as `A_(1),A_(2),A_(3)`. If all three bodies have same mass and maximum velocity then

Options

A. `A_(1)omega_(1)=A_(2)omega_(2)=A_(3)omega_(3)`
B. `A_(1)omega_(1)^(2)=A_(2)omega_(2)^(2)=A_(3)omega_(3)^(2)`
C. `A_(1)^(2)omega_(1)=A_(2)^(2)omega_(2)=A_(3)^(2)omega_(3)`
D. `A_(1)^(2)omega_(1)^(2)=A_(2)^(2)omega_(2)^(2)=A_(3)^(2)omega_(3)^(2)`

Answer

B

Explanation

Given that angular velocity of three bodies are `omega_(1),omega_(2)andomega_(3)` and their respective amplitudes are `A_(1),A_(2)andA_(3)`. Since velocities of three bodies are same
`therefore v_(1)=v_(2)=v_(3) or A_(1)omega_(1)=A_(2)omega_(2)=A_(3)omega_(3)`