The equation of motion of a particle executing simple harmonic motion is `a+16pi^(2)x = 0` In this equation, a is the linear acceleration in `m//s^(2)` of the particle at a displacement x in meter. The time period in simple harmonic motion is

Options

A. `(1)/(4)s`
B. `(1)/(2)s`
C. 1 s
D. 2 s

Answer

A

Explanation

The given equation of SHM is `a=-16pi^(2)x`
Standard equation of SHM is `a=-omega^(2)x`
Comparing two equations, we get `omega=4pi`
`therefore T=(2pi)/(omega)=(2pi)/(4pi)=(1)/(2)s`