Two point masses of 3 kg and 6 kg are attached to opposite ends of horizontal spring whose spring constant is `300 Nm^(-1)` as shown in the figure. The natural vibration frequency of the system is approximately

Options

A. 4 Hz
B. 3 Hz
C. 2 Hz
D. 1 Hz

Answer

B

Explanation

The reduced mass of the system is `mu=(m_(1)m_(2))/(m_(1)+m_(2))`
`T=2pisqrt(((mu)/(k)))=2pisqrt([(m_(1)m_(2))/((m_(1)+m_(2))k)])=2pisqrt(((3)(1))/((4)(300)))=(2pi)/(20)`
`therefore upsilon=(1)/(T)=(20)/(2pi)=3Hz`