A pendulum suspended from the roof of an elevator at rest has a time period `T_(1)`, when the elevator moves up with an acceleration `a` its time period becomes `T_(2)`, when the elevator moves down with an acceleration `a`, its time period becomes `T_(3)`, then

Options

A. `T_(1)=sqrt((T_(2)T_(3)))`
B. `T_(1)=sqrt((T_(2)^(2)+T_(3)^(2)))`
C. `T_(1)=(sqrt(2)T_(2)T_(3))/(sqrt(T_(2)^(2)+T_(3)^(2)))`
D. none of these

Answer

C