There is a rod of length `l` and mass `m`. It is hinged at one end to the ceiling. The period of small oscillation is

Options

A. `T=2pisqrt(((2l)/(3g)))`
B. `T=pisqrt(((l)/(3g)))`
C. `T=2pisqrt(((l)/(3g)))`
D. `T=2pisqrt(((l)/(g)))`

Answer

D

Explanation

As `T=2pisqrt(((I)/(mgh)))`
Here, `I=(ml^(2))/(3)andh=(l)/(2)`
`therefore T=2pisqrt([(((ml^(2))/(3)))/(mg.(l)/(2))])=2pisqrt(((2l)/(3g)))`