The linear density of a vibrating string is `10^(-4) kg//m`. A transverse wave is propagating on the string, which is described by the equation `y=0.02 sin (x+30t)`, where x and y are in metres and time t in seconds. Then tension in the string is

Options

A. 0.09 N
B. 0.36 N
C. 0.9 N
D. 3.6 N

Answer

B

Explanation

Given : `y=0.02sin(x+30t)`
On comparing it wth `y=asin(kx+omegat)`, we get
`k=1` rad `m^(-1)` and `omega=30` rad `s^(-1)`
Velocity of the wave, `v=(omega)/(k)=(30)/(1)=30ms^(-1)`
As `v=sqrt((T)/(mu)) therefore T=v^(2)xxmu=(30)^(2)xx10^(-4)=0.09N`