The velocity of sound waves in air is `330m//s`. For a particluar sound in air, a path difference of `40 cm` is equivalent to a phase difference of `1.6pi`. The frequency of this wave is

Options

A. 165 Hz
B. 150 Hz
C. 660 Hz
D. 330 Hz

Answer

C

Explanation

Here, `v=330ms^(-1)`
As phase difference `=(2pi)/(lambda)xx` path difference
`therefore 1.6pi=(2pi)/(lambda)xx40orlambda=50cm=0.5m`
`therefore upsilon=(v)/(lambda)=(330)/(0.5)=660Hz`