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A string of length 10.0 m and mass 1.25k...

A string of length 10.0 m and mass 1.25kg stretched with a tension of 50N. If a transverse pulse is created at one end of the string, how long does it take to reach the other end ?

A

0.5 s

B

1.0 s

C

1.5 s

D

2.0 s

Text Solution

Verified by Experts

The correct Answer is:
B

Here, tension, `T=50N`
Length of the string, `L=10.0m`
Mass of the string, `m=1.25kg`
`therefore` Mass per unit length is `mu=(1.25kg)/(10.0m)=0.125kgm^(-1)`
The speed of the pulse is
`v=sqrt((T)/(mu))=sqrt((50)/(0.125))=20ms^(-1)`
The time taken by the pulse to reach the other end of the string is
`t=(L)/(v)=(10.0)/(20)=0.5s`
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