If the young's modulus of the material of the rod is `2 xx 10^(11) N//m^(2)` and its density is `8000 kg//m^(3)` then the time taken by a sound wave to traverse 1m of the rod will be

Options

A. `3xx10^(-4)s`
B. `2xx10^(-4)s`
C. `3xx10^(-2)s`
D. `2xx10^(-2)s`

Answer

C

Explanation

The speed of sound waves in the rod is
`v=sqrt((Y)/(rho))=sqrt((2xx10^(11))/(8000))=5000 ms^(-1)`
`therefore` Time taken `=(1)/(5000)=2xx10^(-4)s`