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A metal wire of linear mass density of 9...

A metal wire of linear mass density of `9.8g//m` is stretched with a tension of `10 kg-wt` between two rigid support `1meter` apart. The wire passes at its middle point between the poles of a permanent magnet, and it vibrates in resonance when carrying an alternating current of frequency `n`. the frequency `n` of the alternating source is

A

50 Hz

B

100 Hz

C

200 Hz

D

25 Hz

Text Solution

Verified by Experts

The correct Answer is:
A

At resonance, frequency of ac source
= fundamental frequency of vibration of wire
`therefore upsilon=(1)/(2L)sqrt((T)/(mu))=(1)/(2xx1)sqrt((10xx9.8)/(9.8xx10^(-3)))=(1)/(2)xx10^(2)=50Hz`
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