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A source and an observer approach each other with same velocity 50 m/s. If the apparent frequency is 434 Hz, then the real frequency is (Given velocity of sound = 332 m/s)

A

320 Hz

B

360 Hz

C

390 Hz

D

420 Hz

Text Solution

Verified by Experts

The correct Answer is:
A
Given : `v=332m//s,v_(o)=v_(s)=50m//s`
Both the source and the observer are approaching each other with the same velocity, `therefore upsilon.=upsilon((v+v_(o)))/((v-v_(s)))`
or `434=upsilon((332+50)/(332-50))=(upsilonxx382)/(282)`
or `upsilon=(434xx282)/(382)~~320Hz`
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