A source of sound S is moving with a velocity of `50m//s` towards a stationary observer. The observer measures the frequency of the source as 1000 Hz. What will be the apparent frequency of the source as 1000 Hz. What will be the apparent frequency of the source when it is moving away from the observer after crossing him? The velocity of the sound in the medium is `350m//s`

Options

A. 750 Hz
B. 857 Hz
C. 1143 Hz
D. 1333 Hz

Answer

D

Explanation

Here, `v_(s)=50m//s, v=350m//s`.
When source is moving towards the stationary observer,
`upsilon.(vxxupsilon)/(v-v_(s))`
`therefore upsilon=((v-v_(s))upsilon.)/(v)=((350-50)1000)/(350)=(6000)/(7)Hz`
When source is moving away from the stationary observer,
`upsilon..=(vxxupsilon)/(v+v_(s))=(350)/((350+50))xx(6000)/(7)=750Hz`