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The diplacement of a particle executing ...

The diplacement of a particle executing simple harmonic motion is given by `y=A_(0)+A sin omegat+B cos omegat`. Then the amplitude of its oscillation is given by

A

`A+B`

B

`A_(0)+sqrt(A^(2)+B^(2))`

C

`sqrt(A^(2)+B^(2))`

D

`sqrt(A_(0)^(2)+(A+B)^(2))`

Text Solution

Verified by Experts

The correct Answer is:
C

`y=A_(0)+Asinomegat+Bcosomegat`
`or (y-A_(0))=Asinomegat+Bcosomegat`
or `y.=Asinomegat+Bcosomegat=Acos((pi)/(2)-omegat)+Bcosomegat`
Amplitude `=sqrt(A^(2)+B^(2)+2ABcos.(pi)/(2))[because phi=(pi)/(2)]`
`=sqrt(A^(2)+B^(2))`
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