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Two car moving in opposite directions approach each other with speed of `22m//s` and `16.5m//s` respectively. The driver of the first car blows a horn having a frequency `400 Hz`. The frequency heard by the driver of the second car is [velocity of sound `340m//s`].

A

361 Hz

B

411 Hz

C

448 Hz

D

350 Hz

Text Solution

Verified by Experts

The required frequency of sound heard by the driver of second car is given as
`upsilon.=upsilon((v+v_(o))/(v-v_(s)))`
where v = velocty of sound
`v_(o)` = velocity of observer, i.e., second car
`v_(s)` = velocity of source i.e., first car
`upsilon.=400((340+16.5)/(340-22))=400((356.5)/(318))~~448Hz`
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