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Oxidation number of N in (NH(4))(2)SO(4)...

Oxidation number of `N` in `(NH_(4))_(2)SO_(4)` is

Text Solution

Verified by Experts

Let the oxidation number of N in `(NH_(4))_(2)SO_(4)` molecules is x.
Now,
`2x + (+1xx8) + 6 + (-2xx4)=0`
`2x+8+6-8=0`
x=-3
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