Balance the equation by ion electron method
`MnO_(4)^(-) + Br^(-) to Mn^(2+) + Br_(2)` (acidic medium)

Explanation

To balance the redox reaction \( \text{MnO}_4^{-} + \text{Br}^{-} \rightarrow \text{Mn}^{2+} + \text{Br}_{2} \) in acidic medium using the ion-electron method, we will follow these steps:

### Step 1: Identify Oxidation States
- For \( \text{MnO}_4^{-} \), manganese (Mn) has an oxidation state of +7.
- For \( \text{Mn}^{2+} \), manganese has an oxidation state of +2.
- For \( \text{Br}^{-} \), bromine (Br) has an oxidation state of -1.
- For \( \text{Br}_{2} \), bromine has an oxidation state of 0.

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