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The half cell reactions with reduction p...

The half cell reactions with reduction potentials are
`Pb(s) to Pb^(+2) (aq), E_("red")^(@) =-0.13 V`
`Ag(s) to Ag^(+) (aq) , E_("rod")^(@) =+0.80 V`
Calculate its emf.

Text Solution

Verified by Experts

`E_("cell")^(@)=E_("cathode")^(@)-E_("anode")^(@)`
In given reaction silver (Ag) is reduced and lead (Pb) is oxidised . So,
`E_("cell")^(@)=0.80-(-0.13)`
`=0.93`V
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