Home
Class 12
CHEMISTRY
It has been estimated that the total pow...

It has been estimated that the total power radiated by the sun is `3.8 xx 10^(26)` J per second . The source of energy of stars is a thermonucleur fission reaction . Energy released in the process of fusion is due to mass defect . Q = `Delta mc^(2)`
B.E. per nucleon of `""_(1)^(2) H` and `""_(2)^(4) He` and `1.1` MeV and 7 MeV respectively . If two deutrons nuclei react to form a single helium nucleus , then the energy released is :

A

13.9 Mev

B

26.9 Mev

C

23.6 Mev

D

19.2 Mev

Text Solution

Verified by Experts

The correct Answer is:
C
`Delta m = [ M_("product nucleide") - M_("daughter nucleide")]` , Binding energy = `Deltam _("(amu)") xx 931.5` Mev
Promotional Banner

Topper's Solved these Questions

  • NUCLEAR CHEMISTRY

    AAKASH SERIES|Exercise LECTURE SHEET (LEVEL- II) (EXERCISE - III) (Match the following questions )|3 Videos

  • NUCLEAR CHEMISTRY

    AAKASH SERIES|Exercise LECTURE SHEET (LEVEL- II) (EXERCISE - IV) (Integer answer type Questions)|9 Videos

  • NUCLEAR CHEMISTRY

    AAKASH SERIES|Exercise PRACTICE SHEET - 2 (Integer answer type Questions )|8 Videos

  • NOBLE GASES

    AAKASH SERIES|Exercise PRACTICE SHEET - 2 (Single more than one option questions)|5 Videos

  • PERIODIC TABLE

    AAKASH SERIES|Exercise QUESTIONS FOR DESCRIPTIVE ANSWERS|37 Videos

Similar Questions

Explore conceptually related problems

It has been estimated that the total power radiated by the sun is 3.8 xx 10^(26) J per second . The source of energy of stars is a thermonucleur fission reaction . Energy released in the process of fusion is due to mass defect . Q = Delta mc^(2) Mass equivalent to energy 931 Mev is

It has been estimated that the total power radiated by the sun is 3.8 xx 10^(26) J per second . The source of energy of stars is a thermonucleur fission reaction . Energy released in the process of fusion is due to mass defect . Q = Delta mc^(2) In a nuclear reaction , ""_(1)^(2) H + ""_(1)^(2) H to ""_(2)^(3) He + ""_(0)^(1)n . if the masses of ""_(1)^(2) H & ""_(2)^(3) He are 2.014741 amu and 3.016977 amu respectively . then the Q-value of the reaction is nearly :

The binding energies per nucleon for deuteron (._1H^2) and helium (._2He^4) are 1.1 MeV and 7.0 MeV respectively. Calculate the energy released, when two deuterons fuse to form a helium nucleus.

The binding energy par nucleon for deuterium (""_(1)^(2)H) and helium (""_(4)^(2)He) are 1.1 MeV and 7.0 MeV respectively. The energy released when two deutrons fuse to form a helium nucleus (""_(4)^(2)He) is K(10^(7)) MeV, where K= ……… (nearly)