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The ""(92)^(235) U disintegrates to give...

The `""_(92)^(235) U` disintegrates to give `4 alpha` and `6 alpha` particles . The atomic number of the end product is

A

92

B

96

C

84

D

90

Text Solution

Verified by Experts

The correct Answer is:
D
`""_(92) U^(235) to ""_(Z)X^(A) + 4 (""_(2) He^(4)) + 6 (""_(-1) beta^(0)) , 235 = A + 16 + 0 implies A = 235 - 16 = 219`
`92 = Z + 8 - 6 implies Z = 92 - 2 = 90`
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