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A radioactive substance (parent ) decays...

A radioactive substance (parent ) decays to its daughter element the age of radioactive substance (t) is related to the daughter (d) parent (p) ratio by the equation :

A

`t = (1)/(lambda) "ln" (1 + (p)/(d))`

B

`t = (1)/(lambda) "ln" (1 + (d)/(p))`

C

`t = (1)/(lambda) "ln" ((d)/(p))`

D

`t = (1)/(lambda) "ln" ((p)/(d))`

Text Solution

Verified by Experts

The correct Answer is:
B
`A to D `
`(N_(0) - x) = N^(PX) = N^(D) , (N_(0) - x) = N^(p) , N_(0) - N^(D) = N^(p) , N_(0) = (N^(D) + N^(p))`
`t = (1)/(lambda) xx log ((N^(D) +N^(P))/(N^(P))) , t = (1)/(lambda) xx 1_(n) (1 + (N^D)/(N^P))`
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