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The specific conductance of a saturated ...

The specific conductance of a saturated solution of a salt MX is ` 2.8 xx 10^(-7) Omega^(-1) cm^(-1)` and the equivalent conductances at infinite dilution of `M^(+1)` and `X^(-1)` ions are 68 and `72 Omega^(-1) cm2 `/ equivalent respectively Hence, the `K_(sp)` of MX is found to be

A

`2 xx 10^(-6)`

B

`4 xx 10^(-12)`

C

`10^(-12)`

D

`4 xx 10^(-6)`

Text Solution

Verified by Experts

The correct Answer is:
B
`^^= ^^_(M^(+)) + ^^_(X^(-)) = 68 + 72 , ^^_(M^(+)) = K xx (1000)/(5) (S=M+ " mole/L")`
`68 + 72 = (2.8 xx 10^(-7) xx 1000)/(S) , S = ( 2.8 xx 10^(-7) xx 1000)/(68 + 72) , S = 2 xx 10^(-6)`
`MX implies M^(+) + X^(-) , K_(SP) = [M^(+)][X^(-)], K_(sp) = (S)(S)`
` K_(SP) = S^(2) = (2 xx 10^(-6))^(2) = 4 xx 10^(-12)`
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