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The emf of the cell in which of the foll...

The emf of the cell in which of the following reaction , `Zn_((s)) +Ni^(2+) (0.1 M) to Zn^(2+) (1.0M) + Ni_((s)) ` occurs is found to 0.5105 V at 298 K . The standard emf of the cell is

A

`0.4810 V `

B

`0.5696 V `

C

`-0.5105 V `

D

`0.5400 V `

Text Solution

Verified by Experts

The correct Answer is:
D
`0.5105 = E^(0) -(0.059)/(2) log""(1)/((0.1))`
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