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The resistance R=V/I where V=(100 pm5)V ...

The resistance R=V/I where V=`(100 pm5)V` and I=`(10 pm 0.2)A`. Find the percentage error in R.

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`R=(V)/(I)`
`:.` Percentage error in R,
`=(DeltaR)/(R)xx100=((DeltaV)/(V)+(DeltaI)/(I))xx 100`
`:.(DeltaR)/(R)xx100=((5)/(100)+(0.2)/(10))xx100`
`=(0.05+0.02)xx100`
`=0.07xx100=7%`
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