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100 ml of 0.1 M HCl and 100 ml of 0.1 M ...

`100 `ml of 0.1 M HCl and 100 ml of 0.1 M HOCN are mixed then ` (K_a= 1.2 xx 10^(-6))`

A

`OCN^(-) ` concentration in the solution is `1.2 xx10^(-6) `

B

pH of the solution is 1.3

C

solution is a buffer

D

`H^(+) ` in the solution is `10^(6) `

Text Solution

Verified by Experts

The correct Answer is:
A, B
` HOCN hArr H^(+) +OCN^(-) `
` K_a rArr ([H^(+)][OCN^(-)])/( [HOCN]) `
` 1.2 xx 10 ^(-6) = (5xx 10 ^(_2) [OCN^(-) ])/( 5 xx10 ^(-2)) `
`[ OCN^(-) ]= 1.2 xx 10 ^(-6) `
Approximation method, weak acid conribution is neglected.
` [H^(+) ] =(100 xx 0.1 +0)/( 200) = 0.05 therefore pH =1.3 `
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