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Weak acids and bases are not completely ...

Weak acids and bases are not completely ionised when dissolved in polar medium like water
`H rarr H^(+) +A^(-)`
`{:(t_(0),C,O,O),(t_(eq),C-Calpha,Calpha,Calpha):}`
`K_(a)=(Calpha^(2))/(1-aplha)=Calpha^(2),alphasqrt((K_(a))/(C))`
`:. (alpha_(1))/(alpha_(2))=sqrt((Ka_(1))/(Ka_(2))),(alpha_(1))/(alpha_(2))=sqrt((C_(2))/(C_(1)))`
( For two acids at same conc.) (for same acid at diff conc. )
Relative strength of two weak monoprotic acids may be given as

A

` ([H^(+)])/([H^(+)]_2) `

B

`(alpha _1)/(alpha_2) `

C

` sqrt((Ka1)/(Ka_2))`

D

All of the above

Text Solution

Verified by Experts

The correct Answer is:
D
Relative strength ` = ([H^(+)])/([H^(+)]_2) = (sqrt(K_(a_1)))/(sqrt(K_(a_2)))=(alpha _1)/(alpha_2)`
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