`alpha`-maltose can be hydrolysed to glucose according to the following reaction. Given
Standard enthalpies of formation of `C_(12) H_(22)O_(11)` (aq) = `-2238`kJ/mol
Standard enthalpies of formation of `H_(2)O (l) = -285kJ//mol`
Standard enthalpies of formation of `C_(6)H_(12)O_(6)` (aq) `= -1263kJ//mol`
`{:("Time (min)",0,1.0,100),("Conc. Of -maltose(M)",4.0,1.0,0.25):}`
Which of the following statements(s) is/are true?

Options

A. The hydrolysis of maltose is exothermic
B. Heat liberated in combustion of 1.0 mol of `alpha`-maltose is greater than the heat liberated in combustion of 2.0 mol of glucose
C. Increasing temperature will increase the degree of hydrolysis of `alpha`-maltose
D. The hydrolysis of `alpha`-maltose follow 1st order kinetics

Answer

A, B, C

Explanation

Hydrolysis of Maltose `=2(-1263) - {-2238- 285} = - 2526 + 2523 = -3`
Since `Delta H=` -Ve, the reaction is exothermic so increase of temperature decreases the degree of hydrolysis In the first 50 min, reduction in concentration of `alpha`- maltose = 1/4= 0.25
50 min `(0.25)/(1) = 0.25 :.` It follows `1^(st)` order kinetics